Q. 11. The probability of a college student being male is 1/3 and that of being female is 2/3. The probability that a male student completes the course is 3/4 and that a female student does it is 1/2. A student is selected at random and is found to have completed the course. What is the probability that the student is a male? (Dec. 2001)

Solution. This problem is based on Bayes theorem.
Let A = an event that the student completes the course
B1 = an event that the student selected is male
B2 = an event that the student selected is female

Therefore, P(B1) = 1/3, P(B2) = 2/3
P(A | B1) = 3/4, P(A | B2) = 1/2

 
P(B1) P(A | B1)
P(B1 | A) =
 
P(B1) P(A | B1) + P(B2) P(A | B2)

 
(1/3) X (3/4)
or P(B1 | A) =
 
[(1/3) X (3/4)] + [(2/3) X (1/2)]

or P(B1 | A) = 0.428
Thus, the probability that the student being male is 0.428.



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